Enthalpy of vapourization of a liquid is 54.4 kJ/mole. Entropy of vapourization of liquid will be ( Boiling point of liquid = 2220 c )

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270 J K-1 mol-1

150 J K-1 mol-1

410 J K-1 mol-1

110 J K-1 mol-1

answer is D.

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Detailed Solution

∆Svap= ∆HvapTb; ∆Svap= 54.4×103 J mol-1495 K=109.9 J K-1 mol-1

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