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Q.

Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape

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a

1/8

b

1/4

c

3/8

d

1/2

answer is A.

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Detailed Solution

nH2=nO2 and tH2=tO2According to Graham's lawH2rO2=IO2MH2⇒v1/t1v2/t2=3221/21/x=16=4⇒x2=4 ∴x=8∴ Fraction of O2=1/8
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