Equal volumes of two solutions of a strong acid having pH 3 and pH 4 are mixed together. The pH of the resulting solution will then be equal to

pH = 3 ⇒  H3O+1 = 10-3pH = 4 ⇒  H3O+2 = 10-4As equal volumes are mixed so after mixing( 1+1 = 2 )H3O+1 = 10-32H3O+2 = 10-42H+mixture = 0.5 × 10-3 + 0.5 + 10-4 =0.5×10-31+0.1=5.5×10-4pH=-log5.5×10-4=4-log5.5=4-0.74=3.26