Q.
Equal volumes of two solutions of a strong acid having pH 3 and pH 4 are mixed together. The pH of the resulting solution will then be equal to
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a
3.5
b
3.26
c
7
d
1.0
answer is B.
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Detailed Solution
pH = 3 ⇒ H3O+1 = 10-3pH = 4 ⇒ H3O+2 = 10-4As equal volumes are mixed so after mixing( 1+1 = 2 )H3O+1 = 10-32H3O+2 = 10-42H+mixture = 0.5 × 10-3 + 0.5 + 10-4 =0.5×10-31+0.1=5.5×10-4pH=-log5.5×10-4=4-log5.5=4-0.74=3.26
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