The equation of state of some gases can be expressed as Vander wal equation that is P+a/V2(V-b)=RT ; where p is the pressure, V is the volume, T is the absolute temperature and a,b, R are constants. The dimensions of ‘a’ are:
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a
M1L1T-1
b
M1L-5T1
c
M2L5T-1
d
M1L5T-2
answer is D.
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Detailed Solution
aV2=corrected term of pressure, therefore dimensions of this is equal to dimensions of pressure ML-1T-2 Therefore a[L]6=ML-1T-2 Therefore dimensions of a=M1L5T-2