First slide

Chemical Equilibrium

Question

The equilibrium constant for the following reaction at 298 K is expressed as $x \times 10^{y}$ . $2 F e^{3 +} + 2 I^{-} \to 2 F e^{2 +} + I_{2}, E_{c e l l}^{0} = 0.235 V$ .
The value of y is ______

Moderate

Solution

$Δ G^{0} = - R T$ 2.303 log K
- nFE⁰= - R T ln K
$- 2 \times (.235) \times 96500 = - R \times 298 \times$ 2.303 log K
log K = 8 , therefore k=1x10⁸

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