The equilibrium constant for the following reaction at 298 K is expressed as x×10y. 2Fe3++2I−→2Fe2++I2,Ecell0=0.235 V.The value of y is ______

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answer is 8.

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Detailed Solution

ΔG0=−RT 2.303 log K- nFE0= - R T ln K−2×.235×96500=−R×298× 2.303 log Klog K = 8 , therefore k=1x108

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