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Q.

The equilibrium constant for the following reaction is 10.5 at 500 K. A system at equilibrium has [CO]=0.250M and H2=0.120M what is theCH3OH? CO(g)+2H2(g)⇌CH3OH(g)

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a

0.0378

b

0.0435

c

0.546

d

0.0499

answer is A.

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Detailed Solution

Kc=CH3OH[CO]H22 10.5=[CH3OH]0.250×0.1202 [CH3OH]=0.0378
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