The equilibrium constant for the given reaction is 100. N2(g)+202(g)⇌2NO2(g) What is the equilibrium constant for the reaction given belowNO2(g)⇌12N2(g)+O2(g)

N2+202⇌2NO2            K1=[NO2]2[N2][O2]2 or     100=[NO2]2[N2][O2]2 Again, [NO2]⇌12N2+O2                    K2=[N2]12[O2][NO2] or                   K22=[N2][O2]2[NO2]2 Eqs. (i)×(ii), we get               100×K22=1 or      K22=1100 or K2=110=0.1