Q.

The equilibrium constant for the given reaction is 100. What is the equilibrium constant for the reaction given : at same temperature is

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a

10

b

1

c

0.1

d

0.01

answer is C.

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Detailed Solution

When equilibrium reaction is reversed  new Kc is reciprocal of original Kc Kc for 2 NO2(g) ⇌N2(g) + 2O2(g) is 1100When reversible reaction is divided by number ‘n’ new K/c = Kc1nKc for NO2(g) ⇌12N2(g) + O2(g)  = 1100=110=0.1
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The equilibrium constant for the given reaction is 100. What is the equilibrium constant for the reaction given : at same temperature is