Equilibrium constant of H2g+I2g⇌2HI(g)is 2×10-4. What is the equilibrium concentration of HI, if concentrations of and H2g I2g respectively are 2.2 ×10-2 M and 2.2 ×10-4 M ?

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answer is 3.

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Detailed Solution

KC=HIg2H2gI2gHI=2×10-4×2.2×10-2×2.2×10-412=9.6812×10-5=3.11×10-5 M

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