The equilibrium constant Kp  of reaction NH4HS(s)≅NH3(g)+H2S(g)  is expressed as x×10y . atm2. If the observed pressure of mixture in 20 atm what is ‘Y’?

NH4HS(s)⥂NH3(g)+H2S(g) t = 0 100 Moles of gases at equilibrium = 2xt = eq 1-x x x∴XNH3=x2x=12 &       PNH3=202=10 atm &     ∴XH2S=x2x=12 &       PH2S=202=10 atm ∴KP=10×10=100=1.0×102 atm2