The equilibrium constant, KP for the reaction2SO2(g) + O2(g) ⇋2SO3(g)is 4.0 atm-1 at 1000 K. What would be the partial pressure of O2 if at equilibrium the amount of SO2 and SO3 is the same ?

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16.0 atm

0.25 atm

1 atm

0.75 atm

answer is B.

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Detailed Solution

2SO2(g) + O2(g) ⇋2SO3(g)KP = 4.0 atm-2KP=PSO32PSO22PO2Given that at equilibrium the amount of PSO2 and PSO3 is the same soPSO32PSO22PO2=4 ⇒ PO2=14=0.25 atm

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