Q.

The equilibrium constant Kc for the following reaction at 842oC is 7.90 x 10-3.What is K p at same temperature? 12 F2(g)⇌F(g)

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a

8.64×10-5

b

8.26×10-4

c

7.90×10-2

d

7.56×10-2

answer is D.

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Detailed Solution

kp=kc·(RT)∆ng ∆ng=1-12=12; T=842°c=1115k Kp=7.90×10-3(0.0821×1115)1/2=7.56×10-2
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