Q.
The equilibrium constant of the reactionH2(g) + I2(g) ⇌ 2HI(g) is 64. If the volume of the container is reduced to one-fourth of its original volume, the value of the equilibrium constant will be
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a
16
b
32
c
64
d
128
answer is C.
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Detailed Solution
For this reaction there is no change in equilibrium constant by change of volume.
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