The equilibrium constants for the reactions Zn(s)+Cu2+(aq)⇔Zn2+(aq)+Cu(s), Cu(s)+2Ag(aq)+⇔Cu(aq)2++2Ag(s) are K1 and K2 respectively then the equilibrium constant for the reaction Zn(s)+2Ag(aq)+⇌Zn(aq)+2+2Ag(s) will be
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a
K1+K2
b
K1×K2
c
K1K2
d
K1−K2
answer is B.
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Detailed Solution
overall equillibrium constant is product of equilibrium constant of two reaction