The equilibrium constants for the reactions Zn(s)+Cu2+(aq)⇔Zn2+(aq)+Cu(s), Cu(s)+2Ag(aq)+⇔Cu(aq)2++2Ag(s) are K1 and K2 respectively then the equilibrium constant for the reaction Zn(s)+2Ag(aq)+⇌Zn(aq)+2+2Ag(s) will be

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K1+K2

K1×K2

K1K2

K1−K2

answer is B.

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Detailed Solution

overall equillibrium constant is product of equilibrium constant of two reaction

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