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Q.

For the equilibriumCuSO4 .5H2O(s)  ⇌  CuSO4.3H2O(s) + 2H2O(g)KP=2.25  ×  10-4  atm2  and vapour pressure of water is 22.8 torr at 298 K. CuSO4. 5H2O(s) is efflorescent  (i.e., loses water) when relative humidity is

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a

less than 63.3%

b

less than 50%

c

less than 66.6%

d

above 66.6%

answer is B.

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Detailed Solution

CuSO4 . 5H2O(s) ⇌ CuSO4.3H2O(s)+2H2O(g)KP=2.25  ×  10-4KP=pH2O2= 2.25×10-4pH2O =1.5×10-2Vapour pressure = 22.8760 = 3 × 10-2R.H. = pH2O V.P  ×  100 = 50%Therefore, (2) option is correct.
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