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For the equilibrium H2O(g)⇌H2(g)+12O2(g), the standard Gibb’s free energy change ΔG0 is 5.96k .cal / mole . The equilibrium constant for the reaction at 298K is

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a

4.55×10-5 atm12

b

3.6×10-3 atm12

c

4.55×10-4 atm12

d

3.6×10-6 atm12

answer is A.

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Detailed Solution

ΔG0=-2.303RTlogKP 5.96×1000=-2.303×2×298logKP -4.342=logKP ∴KP=4.55×10-5

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For the equilibrium H2O(g)⇌H2(g)+12O2(g), the standard Gibb’s free energy change ΔG0 is 5.96k .cal / mole . The equilibrium constant for the reaction at 298K is