In the equilibrium A- + H2O   ⇌   HA  +  OH-   Ka = 1.0  ×  10-5.  The degree of hydrolysis of 0.001 M solution of the salt is

Ka = 1.0  ×  10-5Kh = hydrolysis constantKh = KwKa = 10-1410-5 = 10-9Degree of hydrolysis (h) = KhC= 10-90.001 = 10-6 = 10-3 ;   H = 10-3