In the equilibrium A- + H2O ⇌ HA + OH- Ka = 1.0 × 10-5. The degree of hydrolysis of 0.001 M solution of the salt is

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10-3

10-4

10-5

10-6

answer is A.

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Detailed Solution

Ka = 1.0 × 10-5Kh = hydrolysis constantKh = KwKa = 10-1410-5 = 10-9Degree of hydrolysis (h) = KhC= 10-90.001 = 10-6 = 10-3 ; H = 10-3

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