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Q.

For the equilibrium Kp = 0.82 atm at 270C. At the same temperature its Kc in mol lit-1 is (R = 0.082 lit atm mol-1 K-1)

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Detailed Solution

Δng = nP (g) -nR (g)Δng = 2 - 1Δng = 1KP = KC (RT)Δn0.82 = KC (0.0821 ×300)1
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