An equilibrium mixture in a vessel of capacity 100 litre contain 1 mol N2, 2 mol and O2 and 3 mol NO. No. of moles of O2 to be added so that at new equilibrium the conc. of NO is found to be 0.04 mol/lit

N2         +           O2          ⇌      2NO0.01 M                0.02 M               0.03 MKC=0.0320.01  ×  0.02 = 4.5Let a moles of O2 be addedN2         +           O2          ⇌      2NO0.01 - x               0.02 + a - x        0.03 + 2x0.03 + 2x = 0.04⇒         x = 0.005i.e.,        4.5 = 0.0420.015 + a  0.005Moles of O2 added = a x 100 = 10118