Q.

For the equilibrium 2O3(g)⇌3O2(g), the temperature where the value of KP( atm )KC mole.lit -1=2 in kelvin scale is ( gas constant R=0.0821 lit.atm K-1)

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answer is 24.36 .

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Detailed Solution

KP=KC(RT)Δn KP=KC(RT) (∴Δn=1) 2=0.0821×T T=24.36 K

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For the equilibrium 2O3(g)⇌3O2(g), the temperature where the value of KP( atm )KC mole.lit -1=2 in kelvin scale is ( gas constant R=0.0821 lit.atm K-1)