Q.

For  at equilibrium, , where P is equilibrum pressure. Then degree of dissociation of PCl5 at that temperature is

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a

0.75

b

0.25

c

0.9

d

0.5

answer is D.

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Detailed Solution

Let initial moles of PCl5 = 1Degree of decomposition of PCl5 = αEquilibrium pressure = P Total moles at equilibrium = 1 - α + α + α = 1 + αGiven
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For  at equilibrium, , where P is equilibrum pressure. Then degree of dissociation of PCl5 at that temperature is