Q.
For at equilibrium, , where P is equilibrum pressure. Then degree of dissociation of PCl5 at that temperature is
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a
0.75
b
0.25
c
0.9
d
0.5
answer is D.
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Detailed Solution
Let initial moles of PCl5 = 1Degree of decomposition of PCl5 = αEquilibrium pressure = P Total moles at equilibrium = 1 - α + α + α = 1 + αGiven
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