First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

The equivalent conductance of 1N solution of an electrolyte is nearly

Easy

Solution

${\lambda _{eq}} = \kappa \times \frac{{1000}}{N}$

Both λ_eq and κ are taken in CGS units.
Given that N = 1N
${\lambda _{eq}} = \kappa \times \frac{{1000}}{N}\;=10^{3}\times \kappa$

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