Q.
Equivalent conductivity of Al2(SO4)3 is related to its molar conductivity by the expression of
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a
Λeq=Λm3
b
Λeq=6Λm
c
Λeq=Λm6
d
Λeq=Λm
answer is C.
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Detailed Solution
Λeq=k×1000N (N=n×M)Λeq=k×1000n×MForAl2SO43n=6Λeq=Λm6
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