The equivalent mass of a certain bivalent metal is 20. The molecular mass of its anhydrous chloride will be:

Let metal = M, Valency = 2.So, its anhydrous metal chloride = M Cl2.      At. wt. of metal = Eq. wt. x Val  =20×2=40Molecular mass of MCl2 = 40 + (2 x 35.5) = 111 g mol-.