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Q.

The equivalent weight of divalent metal is 32.77. The weight of a single atom is (N0 = 6.023 x1023)

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Detailed Solution

EW of metal = 32.77Valency of metal = 2Aw of metal = (32.77 x 2)                  = 65.465.4g of metal contain 6.023 x 1023 atom'X, g of metal contain 1 atomX = 65.4/NA
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