Equivalent weight of FeS2 in the half reaction, FeS2 → Fe2O3 + SO2 is :
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a
M/10
b
M/11
c
M/6
d
M/1
answer is B.
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Detailed Solution
FeS2 +O2 →Fe2O3 +SO2Balanced reaction is4FeS2 +11O2→2Fe2O3 +8SO21 mole of FeS2=11/4 moles of O2Each O− atom takes 2e− for reduction∴1 O2 molecule takes 4e− NO. of electrons gained by O2 = 4×114 =11∴ Number of e− lost by FeS2=11∴ Equivalent wt of FeS2 in this reaction= M11