Q.

The equivalent weight of iodine in the reaction (M is molecular weight) 2Na2S2O3 + I2 → 2NaI + Na2S4O6  is

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a

M

b

M/2

c

M/3

d

2M

answer is B.

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Detailed Solution

Decrease in Ox.No/atom of Iodine = 1Total decrease in Ox.No/molecule of I2 = 2 x 1 =2EW of I2 =MW/2
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