Q.

The equivalent weight of K4[Fe(CN)6] in the given reaction is:K4Fe(CN)6⟶[0]Fe3++NO3−+CO2

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a

M/20

b

M/1

c

M/60

d

M/61

answer is D.

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Detailed Solution

iron looses 1 esix carbons looses 12 esix nitrogens looses 48 e Net change in oxidation number = + 60 + 1 = + 61  Eq. wt. =M61
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The equivalent weight of K4[Fe(CN)6] in the given reaction is:K4Fe(CN)6⟶[0]Fe3++NO3−+CO2