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Q.

Equivalent weight of KMnO4, in alkaline solution is:

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a

1/5 of molar mass of KMnO4

b

1/6 of molar mass of KMnO4

c

1/3  of molar mass of KMnO4

d

1/10 of molar mass of KMnO4

answer is C.

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Detailed Solution

Reaction in alkaline medium isMn+7O4-+2H2O+3e−⟶Mn+4O2+4OH−∴  Total change in oxidation number of Mn= 7 - 4 = 3and total no. of electrons gained = 3.∴ Eq. wt. of KMnO4 = Molar mass of KMnO43
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