Equivalent weight of KMnO4, in alkaline solution is:
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a
1/5 of molar mass of KMnO4
b
1/6 of molar mass of KMnO4
c
1/3 of molar mass of KMnO4
d
1/10 of molar mass of KMnO4
answer is C.
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Detailed Solution
Reaction in alkaline medium isMn+7O4-+2H2O+3e−⟶Mn+4O2+4OH−∴ Total change in oxidation number of Mn= 7 - 4 = 3and total no. of electrons gained = 3.∴ Eq. wt. of KMnO4 = Molar mass of KMnO43