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Q.

The equivalent weight of a metal in different compounds are 18.6 and 28. Atomic mass of the metal would be

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a

18.6

b

28

c

46.6

d

56

answer is D.

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Detailed Solution

Valency (n-factor) = At.mass(A)Eq.mass(E)Let n-factor is n1 when E1 =18.6Let n-factor is n2 when E2 = 28n1n2=A1E1×E2A2 = 2818.6=32 ( at .mass of element is same)A1 = 18.6×3 =55.8 ≅56A2 = 28 ×2 = 56 =A1
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