The equivalent weight of a metal, 6 g of which evolve 5.6L of H2 at NTP from an acid is:
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a
6
b
12
c
24
d
2.4
answer is B.
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Detailed Solution
Wt. of metal = 6.0 g;volume at NTP = 5.6 L.We know that:Eq. wt. of a metal = wt. of metal VNTP of H2 in L×11.2L∴ Eq. wt. of metal =6.0g5.6L×11.2L=12.0g Ans.