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Q.

The equivalent weight of potassium  permanganate KMnO4 in neutral medium will be

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a

Molecular weight

b

Molecular weight 2

c

Molecular weight 3

d

Molecular weight 5

answer is C.

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Detailed Solution

KMnO4 in neutral medium changes to  MnO2  ;;  MnO4−(+7)⟶MnO2(+4)Thus n-factor = change in O.N=3∴ Eq.wt. = Mol.wt. 3
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