Equivalent weight of a substance varies with valency. Equivalent weight of potassium permanganate in acidic medium is ‘X’ and in neutral medium is ‘Y’ . X:Y is
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answer is 3.
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Detailed Solution
Acidic medium: Mn+7O4-→Mn+2 ; Decrease in oxidation state per mole =5 EW (X) =M5 Neutral medium : Mn+7O4-→Mn+4O2 Decrease in oxidation state per mole =3 EW(Y) =M3∴ X : Y = 3 : 5