The equivalent weight of a tetravalent element is 8, the relative vapour density of its oxide is
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a
16
b
8
c
64
d
32
answer is D.
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Detailed Solution
EW of tetravalent element = 8AW of tetravalent metal=4x8=32EW of Oxide ion = 8AW of Oxide of the element = 16Formula of the oxide of element = X+4O-2=XO2MW of the oxide of the element = 32 + 16(2)=64VD of the oxide of the element = 64/2 =32