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In an estimation of bromine by Carius method, 1.6 g of an organic compound gave 1.88 g of AgBr.The mass percentage of bromine in the compound is_______ (atomic mass, Ag = 108, Br = 80 g mol-1)

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Detailed Solution

50% of Br =Atomic mass of Br Molecular mass of AgBr×Mass of AgBr × 100Mass of compound=80185×1.881.6×100=50%

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In an estimation of bromine by Carius method, 1.6 g of an organic compound gave 1.88 g of AgBr.The mass percentage of bromine in the compound is_______ (atomic mass, Ag = 108, Br = 80 g mol-1)