$\mathrm{Ethene}\underset{\mathrm{Zn}+{\mathrm{H}}_2\mathrm{O}}{\overset{{\mathrm{O}}_3}{\to }}\mathrm{A}\underset{{\mathrm{H}}_2\mathrm{O}}{\overset{{\mathrm{CH}}_3\mathrm{MgBr}}{\to }}\mathrm{B}\underset{413\mathrm{K}}{\overset{\mathrm{Conc}.{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }}\mathrm{C}.$The compound ‘C’ in the reaction is

• A

  ${\mathrm{CH}}_2={\mathrm{CH}}_2$

• B

  ${\mathrm{C}}_2{\mathrm{H}}_5-\mathrm{O}-{\mathrm{C}}_2{\mathrm{H}}_5$

• C

  ${\mathrm{CH}}_3-\mathrm{O}-{\mathrm{C}}_2{\mathrm{H}}_5$

• D

  ${\mathrm{CH}}_3-\mathrm{CH}={\mathrm{CH}}_2$