Ethyl isocyanide on acidic hydrolysis gives ‘X and methanoic aicd. Ethyl isocyanide on reduction with sodium amalgam-ethanol gives ’Y'. ‘X’ and ‘Y’ respectively are

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1° amine; 1° amine

1° amine; 2° amine

2° amine; 2° amine

2° amine; 1° amine

answer is B.

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Detailed Solution

C2H5-N≡C→H3O+C2H5NH2(X)+HCOOH; C2H5-NC→C2H5OHNa-HgC2H5-NH-CH3;(Y)

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