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Evaluate ∆U at 500 K for the processMgs+2HClg→ MgCl2s+H2g; ∆H=-109kcalThe volume change of solids to be ignored

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An Intiative by Sri Chaitanya

a

-204 Kcal

b

-108 Kcal

c

-9 Kcal

d

+9 kcal

answer is B.

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Detailed Solution

∆H=∆U+∆ngRT -109=∆U+-1 × 2 × 5001000kcal -109=∆U-1 kcal ∆U=-109 + 1=-108kcal

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