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Q.

EW of I2 in its reaction with conc.HNO3 is

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a

2545

b

2542

c

25410

d

12710

answer is C.

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Detailed Solution

I02+10HNO3â2HI+5O3+10NO2+4H2OTotal increase in ox. state /mole =2X5=10EW of I2=M10=25410=25.4Alternate method: Increase in ox. state / atom of Iodine = 5EW of I2=AW5=1275=25.4

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