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An excess of AgNO3 is added to 100 mL of a 0.01 solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be

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By Expert Faculty of Sri Chaitanya
a
0.003
b
0.01
c
0.001
d
0.002

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detailed solution

Correct option is C

CrH2O4Cl2Cl+AgNO3→CrH2O4Cl2NO3+AgClppt No. of  mole=0.01×1001000=10−3 So, mole of AgCl=0.001


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