Excess of carbon dioxide is passed through 50 mL, of 0.5 M calcium hydroxide solution. After the completion of the reaction, the solution was evaporated to dryness. The solid calcium carbonate was completely neutralised with 0.1 N hydrochloric acid. The volume of hydrochloric acid required is (Atomic mass of calcium = 40)

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300 cm3

200 cm3

500 cm3

400 cm3

answer is C.

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Detailed Solution

Number of millimoles of Ca(OH)2=50×0.5=25 Number of millimoles of CaCO3=25 Number of milliequivalents of CaCO3=50∴ Volume of 0.1 NHCl=500.1=500 cm3

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