First slide

Ammonia

Question

Excess ${Cl}_{2}$ reacts with ${NH}_{3}$ to give ‘X’. Excess ${NH}_{3}$ reacts with ${Cl}_{2}$ to give ‘Y’. ‘X’ and ‘Y’ are compounds of nitrogen. Oxidation states of nitrogen in ‘X’ and ‘Y’ respectively are

Moderate

A

-3, -3
B

-3, +3
C

+3, -3
D

-3, -5

Solution

${NH}_{3} + 3 {Cl}_{2} \to {\overset{- 3}{N} {Cl}_{3}}_{(x)}^{} + 3 HCl; 8 {NH}_{3} + 3 {Cl}_{2} \to 6 \overset{- 3}{N} H_{4} Cl + N_{2}; (Y)$

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