Q.

Excess of KI reacts with CuSO4 solution, and Na2S2O3 solution is added to it. Which of the following statements is incorrect for the reaction?

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a

Evolved l2 is reduced

b

CuI2 is formed

c

Na2S2O3 is oxidised

d

Cu2l2 is formed

answer is B.

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Detailed Solution

Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.2CuSO4​+4KI→Cu2​I2​↓+I2​+2K2​SO4​Thus, CuI2​ is not formed in this reaction.Hence, the option B is incorrect and option A is correct.The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.2Na2​S2​O3​+I2​→Na2​S4​O6​+2NaIIodine is reduced and sodium thiosulphate  is oxidized.
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Excess of KI reacts with CuSO4 solution, and Na2S2O3 solution is added to it. Which of the following statements is incorrect for the reaction?