Excess of KI reacts with CuSO4 solution, and Na2S2O3 solution is added to it. Which of the following statements is incorrect for the reaction?
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a
Evolved l2 is reduced
b
CuI2 is formed
c
Na2S2O3 is oxidised
d
Cu2l2 is formed
answer is B.
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Detailed Solution
Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.2CuSO4+4KI→Cu2I2↓+I2+2K2SO4Thus, CuI2 is not formed in this reaction.Hence, the option B is incorrect and option A is correct.The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.2Na2S2O3+I2→Na2S4O6+2NaIIodine is reduced and sodium thiosulphate is oxidized.