An exothermic reaction X ® Y has an activation energy 30 kJ mol−1, If energy change DE during the reaction is -20kJ, then the activation energy for the reverse reaction in kJ is _______

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answer is 50 KJ.

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Detailed Solution

ΔE=Eaforward-Eabackward -20 kJ=30 kJ-Ea(backward )Ea(backward )=30+20=50 kJ