Q.

In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO3, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine)

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answer is 2.

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Detailed Solution

Millimoles of solution of chloride=0.05×10=0.5Millimoles of AgNO3 solution=0.1×10=1So, the millimoles of AgNO3 are double than the chloride solution.∴ XCl2+2AgNO3⟶2AgCl+XNO32
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