An experiment revealed that $$100$$ g of silver reacted with all the chlorines in $$55.993$$ g of arsenious chloride [V.D. $$6.3$$, (air=$$ $$1)]. If sp. heat of arsenic is $$0.082$$, calculate the formula of arsenious chloride and exact at. wt. of arsenic (1L$$ of air at NTP weighs $$1.293$$ g; at. wt , $$Ag=$$ $$108$$, $$Cl=$$ $$35.5).

Question

An experiment revealed that $$100$$ g of silver reacted with all the chlorines in  $$55.993$$ g of arsenious chloride [V.D. $$6.3$$, (air=$$ $$1)]. If sp. heat of arsenic is $$0.082$$, calculate the formula of arsenious chloride and exact at. wt. of arsenic (1L$$ of air at NTP weighs $$1.293$$ g; at. wt , $$Ag=$$ $$108$$, $$Cl=$$ $$35.5).

Infinity Learn · Accepted Answer

Wt. of Ag $$=$$ $$100$$ g,Wt. of arsenious $$chloride=$$ $$55.993$$ g. $$1$$ L of air at NTP weighs $$=$$ $$1.293$$ g . ∴$$11.2$$ L of air at NTP $$weighs=$$ $$1.293$$ x $$11.2$$ $$=$$ $$14.48$$ ∴V.D. of air $$=$$ $$14.48$$, V.D. of arsenious chloride  $$=$$ $$6.3$$ X $$14.48$$ $$=$$ $$91.2$$  Approx. at. wt. $$=6.4$$ sp. heat $$=6.40.082=78Mol$$. wt. of AsClx $$=$$ M $$+$$ $$35.5x$$ $$($$ x $$=$$ valency of $$As)$$ $$2$$ x V.D. of AsClx $$=$$ $$78$$ $$+$$ $$35.5x$$ $$2$$×$$91.2=78+35.5x$$;$$182.4$$−$$7835.5=x$$; $$x=104.435.5$$≈$$3$$∴Molecular formula of arsenious chloride $$=AsCl3Also$$, Mol. wt. of $$AsClx=Ex+35.5x$$                           (E$$ $$=$$ Eq. wt. $$=$$ M, i.e., at. wt.$$) or   $$E=182.2$$−$$106.53=25.23$$ ∴Exact at. wt. $$=$$ Eq. wt. x Valency  $$=$$ $$25.3$$ X $$3$$ $$=$$ $$75.9$$

An experiment revealed that 100 g of silver reacted with all the chlorines in 55.993 g of arsenious chloride [V.D. 6.3, (air= 1)]. If sp. heat of arsenic is 0.082, calculate the formula of arsenious chloride and exact at. wt. of arsenic (1L of air at NTP weighs 1.293 g; at. wt , Ag= 108, Cl= 35.5).

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