Experimentally it was found that a metal oxide has formula M0.98O. Metal M, is present as M2+ and M3+ in its oxide. Fraction of the metal which exists as M3+ would be :
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a
7.01%
b
4.08%
c
6.05%
d
5.08%
answer is B.
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Detailed Solution
3x+2(0.98−x)=2x+1.96=2⇒x=0.04% of M3+=0.040.98×100=4.08%