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An Intiative by Sri Chaitanya
a
n2[h24π2m(Ze2/4π∈0)]
b
1n2[h24π2m(Ze2/4π∈0)]
c
n2[4π2mh2(Ze2/4π∈0)]
d
1n2[4π2mh2(Ze2/4π∈0)]
answer is A.
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