0.2 F of electricity is passed through 20 lit of a solution of aqueous solution of NaCl. pH of the solution after electrolysis is ------------------
NaCl(aq) Cl2(g) + H2(g) + OH-
1F = 1 eq of OH-
0.2 F = 0.2 eq of OH-
[OH-] = =0.01;pOH = 2
pH = 14 - 2 = 12
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