0.2 F of electricity is passed through 20 lit of a solution of aqueous solution of NaCl. pH of the solution after electrolysis is ------------------

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answer is 12.

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Detailed Solution

NaCl(aq)→Electrolysis Cl2(g) + H2(g) + OH-1F = 1 eq of OH- 0.2 F = 0.2 eq of OH- [OH-] = 0.220=0.01;pOH = 2pH = 14 - 2 = 12

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