Q.

10 F of electricity is passed through the solutions of silver nitrate, copper sulphate and ferric chloride. The amount of metal deposited at cathode in each case respectively are

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answer is 3.

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Detailed Solution

Ag++1F1mol⟶Ag;Cu2++2F2mol⟶−Cu              1F                          2FFe2++⟶3mol3FFeGram of Ag liberated =108×101=1080gGram of Cu liberated =63.5×102=317.5gGram of Fe liberated =56×103=186.7g
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10 F of electricity is passed through the solutions of silver nitrate, copper sulphate and ferric chloride. The amount of metal deposited at cathode in each case respectively are